Lipalong, moepa o hlalosa hore na mola o otlolohileng o moepa hakae. Ka linako tse ling e bitsoa gradient. Equations for Slope. Moepa o hlalosoa e le "phetoho ho y" holim'a "phetoho ho x" ea mola. Haeba u khetha lintlha tse peli moleng - (x1,y1) le (x2,y2) - u ka bala moepa ka ho arola y2 - y1 ho feta x2 - x1.
Hereof, Na y-intercept ke y1 kapa y2? Haeba re tseba likhokahano tsa lintlha tse peli - (x1, y1) le (x2, y2) - ho latela mola, re ka bala moepa le moepa oa eona. y-thibela ho bona. Moepa, m, ke phetoho ho y (y, kapa y2 – y1), e arotsoe ke phetoho ea x (x, kapa x2 – x1).
X2 le x1 ke eng?
Ho ekelletsa moo U ka khetholla x1 joang ho x2?
Na hoa tsotelleha hore na ntlha ke efe x1 le x2? Ntlha e 'ngoe ke (x1, y1) mme ntlha e nngwe ke (x2, y2). Ha ho tsotellehe hore na ke efe (x1, y1) le hore na ke efe (x2, y2).
Moepa oa 2x 3y =- 15 ke ofe?
Ho arola litekanyetso tse peli tse mpe ho hlahisa boleng bo nepahetseng. Hlophisa bocha 5 5 le 2×3 2 x 3 . Ngola hape ka mokhoa oa ho thibela letsoapo. Ho sebelisa mokhoa oa ho thibela letsoapo, moepa o 23 .
U fumana y2 joang? U ka re x2 = x1 + bophara . Bophahamo bo sebetsa ka tsela e ts'oanang, ho joalo y2 = y1 + bophahamo .
U bala y1 joang u le hole?
U re mokhoa oa ho fapana joang?
Hape Sebaka se pakeng tsa lintlha ke sefe? Sebaka pakeng tsa lintlha tse peli se hlalosoa e le bolelele ba mola o otlolohileng o hokahanyang lintlha tsena ka sefofane sa khokahano. Sebaka sena se ke ke sa ba mpe, ka hona re nka boleng bo felletseng ha re ntse re fumana sebaka se lipakeng tsa lintlha tse peli tse fanoeng.
U fumana y1 joang?
Sebaka se pakeng tsa lintlha tse peli se khethoa joang? Ithute ho fumana sebaka se pakeng tsa lintlha tse peli ka ho sebelisa mokhoa oa hole, e leng ts'ebeliso ea theorem ea Pythagorean. Re ka ngola hape theorem ea Pythagorean joalo ka d=√((x_2-x_1)²+(y_2-y_1)²) ho fumana sebaka se pakeng tsa dintlha tse pedi.
Y1 ke eng ka sebopeho sa letsoapo?
Mothapo o fetang lintlheng o na le moepa ofe (- 5'4 le 3 2?
Letsoapong ke 4 .
U etsa joang 3x 4y 8? Topics
- 3x – 4y = 8. 3x−4y=8. Kenya 4y mahlakoreng ka bobeli. Kenya 4y mahlakoreng ka bobeli.
- 3x=8+4y. 3x=8+4y. Equation e ka sebopeho se tloaelehileng. Equation e ka sebopeho se tloaelehileng.
- 3x=4y+8. 3x=4y+8. Arola mahlakore ka bobeli ka 3. Arola mahlakore ka bobeli ka 3.
- frac{3x}{3}=frac{4y+8}{3} 33x=34y+8 Ho arola ka 3 ho etsolla katoloso ka 3.
2x 3y ke eng ka mokhoa oa ho thibela letsoapo? Kakaretso: Mokhoa oa ho thibela letsoapo oa mola oa equation 2x + 3y = 6 o fanoe ke y = (-2/3)x + 2.
Sekhahla sa Y 4x 8 ke eng?
y = 4x - 8 e na le moepa oa 4.
Na hoa tsotelleha hore na x1 le x2 ke efe? Ntlha e ’ngoe ke (x1, y1) ’me ntlha e ’ngoe ke (x2, y2). Ha ho tsotellehe hore na ke eng (x1, y1) le e leng (x2, y2).
X1 le x2 ke eng ka lipalo-palo?
xi e emela boleng ba ith ba mofuta oa X. Bakeng sa lintlha, x1 = 21, x2 = 42, joalo-joalo. … Bakeng sa lintlha, Σxi = 21 + 42 +… + 52 = 290.
Sebaka se pakeng tsa lintlha tse peli x1 y1 le x2 y2 ke sefe? Sebaka se pakeng tsa lintlha tse peli P(x1,y1) le Q(x2,y2) se fanoa ke: d (P, Q) = √ (x2 - x1) 2 + (y2 - y1) 2 {Foromo ea sebaka} 2. Sebaka sa ntlha P (x, y) ho tloha tšimolohong se fanoa ke d (0, P) = √ x2 + y2. 3. Equation ea x-axis ke y = 0 4.
U fumana sebaka se pakeng tsa x1 y1 le x2 y2 joang?
Foromo ea hole ke √[(x2-x1)²+(y2-y1)²]. U ka nahana ka eona e le katoloso ea theorem ea Pythagorean!
Sebaka se pakeng tsa lintlha f 3/4 le H 6 8 ke sefe? Sebaka pakeng tsa lintlha ke 29 kapa 5.385 ho pota sekete se haufi.