Qaabka isku dhafan waa: nCr = n! / ((n u2013 r)! r!) n = tirada alaabta.
Halkan, Sideed u xisaabisaa tusaalaha isku dhafka ah? Qaabka isku dhafka ah waxaa loo isticmaalaa in lagu helo tirada siyaabaha lagu dooranayo shay ka mid ah ururinta, sida habka xulashada uusan macno lahayn.
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Formula for Combination.
Qaanuunka Isku-dhafka | nCr=n!(nu2212r)!r! nCr = n! ( n u2212 r ) ! r! |
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Qaanuunka Isku-dhafka Isticmaalka Permutation | C (n, r) = P(n,r)/ r! |
Waa maxay isku darka tusaale? Isku-darku waa xulashada dhammaan ama qayb ka mid ah walxaha, iyada oo aan loo eegin sida ay u kala horreeyaan walxaha loo soo xulay. Tusaale ahaan, ka soo qaad in aynu haysano saddex xaraf oo kala ah: A, B, iyo C. … Doorasho kasta oo suurtagal ah waxay noqon doontaa tusaale isku darka ah. Liiska dhamaystiran ee xulashooyinka suurtogalka ah waxay noqon doonaan: AB, AC, iyo BC.
Intaa waxa dheer waa maxay habka ugu fudud ee loo xisaabiyo isku darka?
Waa maxay qiimaha 8C5? (n-r)! 8C5=8!
Waa maxay qiimaha 5c 2?
5 DOORASHADA 2 = 10 isku -darka suurtagalka ah. 10 waa tirada guud ee dhammaan isku darka suurtogalka ah ee lagu dooranayo 2 walxood markiiba laga bilaabo 5 walxood oo kala duwan iyada oo aan la tixgalinayn siday u kala horreeyaan walxaha tirakoobka & sahanka itimaalka ama tijaabooyinka.
Waa maxay qiimaha 8 isku darka 5? (n-r)! = (8-5) (8-5) = 3!
Waa maxay qiimaha 10 C 3? C3= 10! /3! (7)!
Waa maxay qiimaha 6C4?
(n-r)! r! 6C4=6!
Sidoo kale waa maxay qiimaha 7v4? Soo koobid: Dareenka ama isku darka 7C4 is 35.
Waa maxay jawaabta 5C3?
Combinatorics iyo Pascal's Triangle
0C0 = 1 | ||
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2C0 = 1 | 2C1 = 2 | |
3C0 = 1 | 3C2 = 3 | |
4C0 = 1 | 4C1 = 4 | 4C2 = 6 |
5C1 = 5 | 5C3 = 10 |
Waa maxay macnaha 3C2? 3v2. =3! (2!) (3-2)! =3!
Waa maxay qiimaha 10 C 4?
Sharaxaad tallaabo-tallaabo ah:
10 dooro 4 = 201 isku -darka suurtagalka ah. 201 waa tirada guud ee dhammaan isku darka suurtogalka ah ee lagu dooranayo 4 walxood markiiba laga bilaabo curiyeyaasha kala duwan iyada oo aan la tixgalinayn sida ay u kala horreeyaan walxaha tirakoobka & sahanka itimaalka ama tijaabinta.
Waa maxay qiimaha 6 C 2?
Soo hel 6C2. 6C2 = 6!/(6-2)! 2! = 6! / 4!
Immisa isku darka tirooyinka 1 2 3 4 ayaa jira? Sharaxaad: Haddii aynu eegayno tirada tirooyinka aynu samayn karno annagoo adeegsanayna tirooyinka 1, 2, 3, iyo 4, waxaynu u xisaabin karnaa habka soo socda: lambar kasta (kumanan, boqollaal, tobnaad, kow), waxaanu haynaa 4. doorashada tirooyinka. Oo sidaas daraaddeed waxaan samayn karnaa 4×4×4×4=44=256 lambar.
Sideed u xalin kartaa 10 Qodob? waa 362,880. Isku day inaad xisaabiso 10! 10! = 10×9!
Waa maxay 4C1?
4 DOOR 1 = 4 isku darka suurtogalka ah. Sharaxaada: Hadda sida ay wax u dhacaan Haddaba, 4 waa tirada guud ee dhammaan isku darka suurtogalka ah ee lagu dooranayo 1 curiye markiiba laga bilaabo 4 walxood oo kala duwan iyada oo aan la tixgalinayn sida ay u kala horreeyaan walxaha tirakoobka & sahanka itimaalka ama tijaabooyinka. Mahadsanid 0.
Waa maxay qiimaha 5C1? Combinatorics iyo Pascal's Triangle
2C0 = 1 | 2C2 = 1 | |
3C0 = 1 | 3C2 = 3 | |
4C0 = 1 | 4C1 = 4 | 4C3 = 4 |
5C1 = 5 | 5C3 = 10 |
Waa maxay qiimaha 6P4?
⇒6P4=6! (6-4)! =6!
Waa maxay isku darka 15c3? 0
Waa maxay 4C2 isku darka?
Waxaan ognahay in qaacidada loo isticmaalo in lagu xalliyo tibaaxaha isku dhafan ay bixiyaan: … Ku beddelka n = 4 iyo r = 2 ee qaaciidada sare, 4C2 = 4!/[2! (4–2) = 4!/ (2!
Waa maxay 7c3? 8×7×6=336. C7,3=7!( 3!)( 7-3)!= 7!
Sideed u xallisaa 5P2?
5P2 = 5! / (5-2) = 5x4x3! / 3!
Sideed ku samaysaa 5C3 xisaabiyaha?
Waa maxay 10C7?
⇒10C7=10! 7! ×3! =10×9×8×7×6×5×4×3×2 7×6×5×4×3×2 ×3×2. =10×9×83×2=120.
Waa maxay 5C4 isku darka?
nCr=(r!)(n-r)! maaha! Markaa, 5C4=(4!)(