Iko kusanganisa fomula ndeiyi: nCr = n! / ((n u2013 r)! r!) n = huwandu hwezvinhu.
Hereof, Unoverenga sei musanganiswa muenzaniso? Musanganiswa unoshandiswa kutsvaga nhamba yenzira dzekusarudza zvinhu kubva muunganidzwa, zvekuti kurongeka kwesarudzo hakuna basa.
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Formula for Combination.
Combination Formula | nCr=n!(nu2212r)!r! n C r = n! (n u2212 r)! r! |
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Musanganiswa Formula Uchishandisa Permutation | C(n, r) = P(n, r)/r! |
Chii chinosanganiswa nemuenzaniso? Mubatanidzwa isarudzo yezvose kana chikamu cheseti yezvinhu, pasina kutarisisa marongero anosarudzwa zvinhu. Semuenzaniso, ngatitii tine seti yemabhii matatu: A, B, uye C. … Imwe neimwe inogoneka sarudzo yaizova muenzaniso wekusanganiswa. Rondedzero yakazara yezvingangosarudzwa zvingave: AB, AC, uye BC.
Uyezve Ndeipi nzira iri nyore yekuverenga misanganiswa?
Chii chakakosha che8C5? (n−r)! 8C5=8!
Chii chakakosha che5c 2?
Sarudza 5 = Zviuru gumi zvinokwanisika kusanganiswa. 10 ndiyo huwandu hwese musanganiswa unobvira pakusarudza zvinhu zvitatu panguva kubva pazvinhu gumi zvakasarudzika usingatarise marongero ezvinhu mumatanho & ongororo kana mikana.
Chii chakakosha che8 musanganiswa 5? (n–r)! = (8 – 5)! (8-5)! = 3!
Chii chakakosha che10 C 3? C3= 10! / 3! (7)!
Chii chakakosha che6C4?
(n−r)! r! 6C4=6!
Zvakare Chii chakakosha che7v4? Summary: Kubvumidzwa kana kusanganiswa kwe 7C4 is 35.
Ndeipi mhinduro ye5C3?
Combinatorics uye Pascal's Triangle
0C0 = 1 | ||
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2C0 = 1 | 2C1 = 2 | |
3C0 = 1 | 3C2 = 3 | |
4C0 = 1 | 4C1 = 4 | 4C2 = 6 |
5C1 = 5 | 5C3 = 10 |
3C2 inorevei? 3v2. =3! (2!) (3-2)! =3!
Ndeipi kukosha kwe10 C 4?
Nhanho-nhanho-tsananguro:
10 sarudza 4 = Zviuru gumi zvinokwanisika kusanganiswa. 201 ndiyo nhamba yese yezvisanganiswa zvese zvinogoneka zvekusarudza zvinhu zvina panguva imwe kubva kune dzakasiyana zvinhu pasina kutarisisa kurongeka kwezvinhu muhuwandu & ingangoita ongororo kana kuyedza.
Ndeipi kukosha kwe6 C 2?
Tsvaga 6C2. 6C2 = 6!/(6-2)! 2! = 6! / 4!
Ingani misanganiswa yenhamba 1 2 3 4 iripo? Tsanangudzo: Kana tichitarisa huwandu hwenhamba dzatinokwanisa kugadzira tichishandisa nhamba 1, 2, 3, na4, tinogona kuverenga nenzira inotevera: padijiti imwe neimwe (zviuru, mazana, gumi, zvimwechete), tine 4. sarudzo dzenhamba. Uye saka tinogona kugadzira 4×4×4×4=44=256 nhamba.
Iwe unogadzirisa sei 10 Factorials? zvakaenzana ne362,880. Edza kuverenga gumi! 10! = 10 × 9!
Chii chinonzi 4C1?
4 SARUDZA 1 = 4 inogona kusanganiswa. Tsanangudzo: Zvino maitikiro azvinoita Saka, 4 ndiyo nhamba yese yezvese zvinogoneka musanganiswa wekusarudza elementi imwe panguva kubva kuzvinhu zvina zvakasiyana pasina kutarisisa marongero ezvimiro muhuwandu & ongororo yezvingangoita kana zviedzo. Ndatenda 1.
Chii chakakosha che 5C1? Combinatorics uye Pascal's Triangle
2C0 = 1 | 2C2 = 1 | |
3C0 = 1 | 3C2 = 3 | |
4C0 = 1 | 4C1 = 4 | 4C3 = 4 |
5C1 = 5 | 5C3 = 10 |
Chii chakakosha che6P4?
⇒6P4=6! (6−4)! =6!
Chii chinonzi 15c3 musanganiswa? 0
Chii chinonzi 4C2 musanganiswa?
Tinoziva kuti fomula yakashandiswa kugadzirisa misanganiswa yezvirevo inopiwa ne: … Kutsiva n = 4 uye r = 2 muformula iri pamusoro, 4C2 = 4!/[2! (4-2)!] = 4!/ (2!
Chii chinonzi 7c3? 8×7×6=336. C7,3=7!( 3!)( 7−3)!= 7!(
Iwe unogadzirisa sei 5P2?
5P2 = 5! / (5 – 2)! = 5x4x3! / 3!
Iwe unoita sei 5C3 pane karukureta?
Chii chinonzi 10C7?
⇒10C7=10! 7! ×3! =10×9×8×7×6×5×4×3×2 7×6×5×4×3×2 ×3×2. =10×9×83×2=120.
Chii chinonzi 5C4 musanganiswa?
nCr=(r!)( n−r)! kwete! Saka, 5C4=(4!)(