Domain da Rage na Ayyukan Trigonometric
aiki | domain | range |
---|---|---|
ku 03b8 | R u2013 {nu03c0, n u2208 Z} | R |
dakika 03b8 | R u2013 {(2n+1) u03c0/2, n u2208 Z} | (u2013 u221e, -1] u222a [1, u221e) ko, {y: y u2208 R, y u2265 1 ko y u2264 u20131} |
ku 03b8 | R u2013 {nu03c0, n u2208 Z} | (u2013 u221e, -1] u222a [1 , u221e) ko, {y: y u2208 R, y u2265 1 ko y u2264 u20131} |
Anan, Ta yaya kuke samun yanki da kewayon secant da Cosecant?
Shin secant yana da iyaka? Ba a bayyana aikin ba a 90, kuma kusantar 90 daga hagu yana karkata zuwa ga rashin iyaka, yayin da kusantar 90 daga dama yana karkata zuwa rashin iyaka mara kyau. A wannan yanayin, iyakar wani yanki ba ya wanzu. Don aikin ƙungiya, wannan zai faru a 90 kuma a kowane tazara na 180 ko dai daga gare ta.
Bugu da ƙari Menene kewayon sec 2x? Ana samun ƙananan iyaka na kewayon yanki ta hanyar musanya ma'auni mara kyau na ƙididdiga a cikin lissafin. Ana samun iyaka na sama na kewayon secant ta hanyar musanya ingantacciyar ma'auni na ƙididdiga a cikin ma'auni. Kewayon shine y≤-1 y ≤ - 1 ko y≥1 y ≥ 1 .
Menene yankin sec 2? yankin dakika 2(x)
x 2 | x □ | · |
---|---|---|
(☐) ' | ddx ku | θ |
Menene yanki da kewayon Secx?
jadawali na aikin secant yayi kama da haka: Yankin aikin y=sec(x)=1cos(x) shine kuma duk lambobi na gaske sai dai dabi'u inda cos(x) yayi daidai da 0, wato, dabi'u π2 +πn ga duk lamba n . Kewayon aikin shine y≤-1 ko y≥1 .
Menene madaidaicin yanki na 0? Sashin shine ma'anar cosine. Ƙashin 0 yana da ma'ana da kyau, kuma shine 1. Don haka, sashin 0 kuma shine 1. Kuma murabba'in mazhabar 0 shine. 1² = 1.
Menene yankin Sinx? Hoton y=sin(x) yana kama da igiyar ruwa wanda har abada yana jujjuyawa tsakanin -1 da 1, a cikin siffa mai maimaita kanta kowace raka'a 2π. Musamman, wannan yana nufin cewa yankin zunubi(x) duk ainihin lambobi ne, kuma kewayon shine [-1,1].
Menene yanki da kewayon?
Yankin aiki shine saitin ƙimar da aka ba mu damar toshe cikin aikinmu. Wannan saitin shine ƙimar x a cikin aiki kamar f(x). Iyakar aikin shine saitin ƙimar da aikin ke ɗauka.
Hakanan menene kewayon Arctan? Yankin arctan(x) duk lambobi ne na gaske, kewayon arctan daga −π/2 zuwa π/2 radians keɓantacce . Ana iya ƙaddamar da aikin arctangent zuwa hadaddun lambobi. A wannan yanayin yankin duk hadadden lambobi ne.
Ina Secx ba a bayyana ba?
Yin nazarin Hotunan y = sec x da y = cscx
Lura cewa aikin ba a fayyace ba lokacin da cosin ya kasance 0, yana kaiwa ga asymptotes a tsaye atπ2, 3π2, 3π 2, da dai sauransu. Saboda cosine bai taɓa wuce 1 a cikakkiyar ƙima ba, secant, kasancewa mai ma'ana, ba zai taɓa zama ƙasa da 1 a cikakkiyar ƙimar ba.
Menene madaidaicin madauri na pi sama da 3? Madaidaicin ƙimar daƙiƙa (π3) sec ( π 3 ) ita ce 2 .
Menene daidai Sec 2 theta?
TRIGONOmetric Identity
a) | zunubi 2 θ + ku 2 θ | 1. |
---|---|---|
b) | 1 + tan 2 θ | dakika 2 θ |
c) | 1 + farashi 2 θ | csc 2 θ |
a') | zunubi 2 θ | 1 - ku 2 θ. |
cos 2 θ | 1 - zunubi 2 θ. |
Menene dabara na secant?
Tsawon hypotenuse, lokacin da aka raba shi da tsawon gefen kusa, zai ba da sashin kusurwa a cikin madaidaicin alwatika. Don haka, tushen tsarin sa shine: sec X = frac {Hypotenuse}{A gefen gefen} Hakanan, shine madaidaicin ƙimar cosine.
Menene yankin TANX? Domain: Don haka yankin f(x): = tanx shine duk ainihin lambobi sai dai x = π 2 + kπ, k lamba. Duk ayyukan trig na lokaci-lokaci don haka ba su zama ɗaya-zuwa ɗaya ba.
Menene yankin Ln? Don haka yankin shine (0+∞). Abubuwan fitarwa don ln ba shi da iyakancewa: kowane lamba na gaske yana yiwuwa. Don haka kewayon shine R ko (-∞ +∞).
Menene yankin SEC θ?
Yankin na sec(θ) shine duk wani lamba na gaske cewa. lokacin da aka cire π2, ba adadi ba ne na π . A cikin bayanan lissafi, shine. {x∣x=(k+12)π,kRZ} Lura cewa yanki na sec(θ) da tan(θ) iri daya ne.
Yaya ake rubuta zangon? Lura cewa yanki da kewayon ana rubuta su koyaushe daga karami zuwa manyan dabi'u, ko daga hagu zuwa dama don yanki, kuma daga ƙasan jadawali zuwa saman jadawali don kewayo.
Taya zaka sami zangon?
Ana lissafin kewayon ta cire mafi ƙarancin ƙima daga mafi girman ƙima.
Yaya kuke samun kewayon f? Gabaɗaya, matakai don gano kewayon aiki a algebra ta hanyar su ne:
- Rubuta y=f(x) sannan a warware ma'auni don x, bada wani abu na nau'in x=g(y).
- Nemo yankin g(y), kuma wannan zai zama kewayon f(x). …
- Idan kamar ba za ku iya warwarewa don x ba, to gwada zana aikin don nemo kewayon.
Me yasa kewayon arcsin?
Yana nufin cewa akwai a,b∈[0;π], a≠b, zunubi (a) = zunubi(b). Wannan yana da matukar damuwa saboda Arcsin zai zama multivalued. Ga hujja ɗaya za a sami ƙima biyu. Shi ya sa aka zaɓi irin wannan kewayon cewa zunubi allura ne don haka arcsin aiki ne.
Menene kewayon arcsin? Wannan bambance-bambancen aikin sine, an rage shi zuwa tazara inda yake tazara kuma ya cika duka kewayo, yana da aikin sabanin da ake kira y=arcsin(x) . Yana da iyaka [-π2,π2] da yanki daga -1 zuwa 1.
Me yasa aka iyakance kewayon arcsin?
An iyakance kewayon arcsin(x). saboda in ba haka ba, ƙimar da aka bayar na x zai haifar da kusurwoyi da yawa (yawan kusurwoyi marasa iyaka). Wannan zai sa arcsin(x) mara iyaka ya zama aiki.
Wane kusurwa ne ba a bayyana shi ba? Secant shine ma'anar cosine, don haka sashin na kowane kusurwa x wanda cos x = 0 dole ne ba a bayyana shi ba, tun da zai sami ma'auni daidai da 0. Darajar cos (pi/2) ita ce 0, don haka sashin (pi)/2 dole ne ba a bayyana shi ba.
Menene madaidaicin yanki na pi sama da 4?
Madaidaicin ƙimar daƙiƙa (π4) sec ( π 4 ) ita ce 2-2 .
Shin girman murabba'i na secant yana daidai da murabba'in 1 fiye da murabba'in cosine?
An raba sashin x 1 ta cosine na x: dakika x = 1 cos x , kuma an siffanta cosecent na x ya zama 1 kashi na sine na x: csc x = 1 zunubi x . = tan 5π 4 .
Ina SEC 2x ba a bayyana ba? secx ba a bayyana a -π2 da π2 , don haka ba ya ci gaba a kan rufaffiyar tazara, [-π2,π2]. Yana ci gaba akan buɗaɗɗen tazara (-π2,π2).